Find the equation of a parabola that has a vertex (3,5) and passes through the point (1,13)

y = 2( x-3)^2 +5

Step-by-step explanation:

The vertex form of a parabolic functions is

y = a( x-h)^2 +k

where (h,k) is the vertex

y = a( x-3)^2 +5

Substituting the point into the equation

13 = a( 1-3)^2 +5

13 = a*( -2)^2 +5

13 = 4a +5

Subtract 5

8 = 4a

Divide by 4

8/4 =a

2=a

y = 2( x-3)^2 +5

tangent

Step-by-step explanation:

A common way to remember this is SOHCAHTOA:

SOH means sine = opposite over the hypotenuse

CAH means cosine = adjacent over the hypotenuse

TOA mean tangent = opposite over adjacent