kyliech023
30.06.2019 •
Mathematics
Find the equation of the circle whose center is at (4, 5) and that contains (13, −1).
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Ответ:
(x-4)^2+(y-5)^2=R^2
if you replace the (13, -1) with x and y the R^2 will be 117
(x-4)^2+(y-5)^2=117
Ответ:
Cara's mistake was in letting c be a leg length instead of the length of the hypotenuse.
Step-by-step explanation:
chart shows documented error.