Mathematics: find the equation of the line passing through the point (0,1) which is perpendicular to the line y=-3/4x-3

find the equation of the line passing through

lexhorton2002

29.01.2022

y = $\frac{4}{3}$ x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - $\frac{3}{4}$ x - 3 ← is in slope- intercept form

with slope m = - $\frac{3}{4}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{3}{4} }$ = $\frac{4}{3}$

The line crosses the y- axis at (0, 1 ) ⇒ c = 1

y = $\frac{4}{3}$ x + 1 ← equation of perpendicular line

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campbellcameca

19.10.2021

(x−2)^2=16(y+1)

Step-by-step explanation:

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