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sebasp42
08.08.2019 •
Mathematics
Find the equation of the normal to the curve x^2+y^2+xy=0 at the point (2,2).
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Ответ:
5y -x=8
Step-by-step explanation:
We have given![x^2+y^2+xy=0](/tpl/images/0173/0766/6825a.png)
Differentiating this function with respect to x
At point (2,2)
that is m= -5
The equation of normal is![]\frac{y-y_1}{x-x_1}=\frac{-1}{m}[/tex[tex]\frac{y-2}{x-2}=\frac{-1}{-5}](/tpl/images/0173/0766/93457.png)
5y-x=8 this is the equation of normal
Ответ: