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stacy99
01.03.2020 •
Mathematics
Find the equation of the pair of lines perpendicular to the lines pair represented by the equation ax^2-2hxy+by^2=0 and passing through the origin.
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Ответ:
The equation of the pair of lines perpendicular to the lines given equation is
.
Solution:
Given equation is
.
Let
and
be the slopes of the given lines.
Sum of the roots =![-\frac{\text {coefficient of } x y}{\text {coefficient of } y^{2}}](/tpl/images/0529/5157/534f4.png)
Product of the roots =![-\frac{\text {coefficient of } x^2}{\text {coefficient of } y^{2}}](/tpl/images/0529/5157/088d2.png)
The required lines are perpendicular to these lines.
Slopes of the required lines are![$-\frac{1}{m_{1}} \text { and }-\frac{1}{m_{2}}](/tpl/images/0529/5157/086fd.png)
Required lines also passes through the origin,
therefore their y-intercepts are 0.
Hence their equations are:
Do cross multiplication, we get
Add x on both sides of the equation, we get
Therefore, the joint equation of the line is
Substitute (1) and (2), we get
To make the denominator same, multiply and divide first term by b.
Do cross multiplication, we get
Hence equation of the pair of lines perpendicular to the lines given equation is
.
Ответ:
A= 1/2 S -5