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861819
18.11.2019 •
Mathematics
Find the exact distance between the line 6x-y=-3 and the point (6,2). show your work. explain your answer.
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Ответ:
The distance between line 6 x - y = - 3 and point (6,2) is![\sqrt{37}](/tpl/images/0379/7695/6bf55.png)
Step-by-step explanation:
Given equation of line as :
6 x - y = - 3
And The points be ( 6 , 2 )
Let The distance between line and points = d
So , from point to line distance formula
d =![\frac{\begin{vmatrix}ax & + by & + c\end{vmatrix}}{\sqrt{a^{2}+b^{2}}}](/tpl/images/0379/7695/ef9ff.png)
Or, d =![\frac{\begin{vmatrix}6x & - y & + 3\end{vmatrix}}{\sqrt{6^{2}+(-1)^{2}}}](/tpl/images/0379/7695/5000e.png)
∵ points is ( 6 , 2 )
so, d =![\frac{\begin{vmatrix}6\times 6 & + (-1)\times 2 & + 2\end{vmatrix}}{\sqrt{6^{2}+(-1)^{2}}}](/tpl/images/0379/7695/ad857.png)
or, d =![\frac{36-2+3}{\sqrt{37} }](/tpl/images/0379/7695/38c76.png)
∴ d =![\frac{37}{\sqrt{37} }](/tpl/images/0379/7695/fd632.png)
I.e d =![\sqrt{37}](/tpl/images/0379/7695/6bf55.png)
Hence The distance between line 6 x - y = - 3 and point (6,2) is
Answer
Ответ:
37 degrees is the answer
Step-by-step explanation:
as they are alredy congurent given in the question we can see that both j and q are placed first in the congurence letters given so j=q