genyjoannerubiera
31.07.2021 •
Mathematics
Find the extrema of the function y=cos2x
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Ответ:
Step-by-step explanation:
Find derivative of the function:
y' = -2·sin(2·x)
-2·sin(2·x) = 0
x1 = 0
x2 = 3.142
f(0) = 1
f(3.142) = 1
Answer
fmin = 1, fmax = 1
Ответ:
0.75 FRIST PART SECOND PART 5.75
Step-by-step explanation:
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