simrankaurdhatt
25.02.2020 •
Mathematics
Find the gradient of the straight line with the equation 7x+4y+2=0and find the intercepts on the x and y-axis.
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Ответ:
Step-by-step explanation:
Given that
7x+4y+2=0
There are two ways to find the slope or gradient if the graph
1. Find the derivative with respect to x
2. Or comparing the equation to equation of a line y=mx+c
Using the first step
7x+4y+2=0
Differentiating with respect to x
7+4dy/dx+0=0
4dy/dx=-7
Then, dy/dx=-7/4
The slope is -7/4
2. Using the equation of a line
7x+4y+2=0
Let rearrange the equation and make y the subject of the formular
4y=-7x-2
Divide through by 4
4y/4=(-7x/4)-(2/4)
y=-7/4 x — 1/2
Comparing this to equation of a line y=mx+c,
Then m=-7/4. And the intercept c=-1/2
Now find intercept on x axis
The intercept on axis x means at y=0
Then
7x+4y+2=0
y=0
7x+0+2=0
7x=-2
Then, x=-2/7.
The intercept on the x axis is -2/7
Also intercept on y axis, i.e. at x=0
7x+4y+2=0
0+4y+2=0
4y+2=0
4y=-2
y=-2/4
y=-1/2.
Then intercept on the y axis is -1/2
Ответ:
i think it's c
Step-by-step explanation:
it's just a guess cuz how are we going to know if we cant hear it