Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

Finding the horizontal and oblique asymptote of
f(x)= (-3x^2+7x+1)/(x-2)

Solution:

For Horizontal Asymptote:
Line y=L is a horizontal asymptote of the function y=f(x), if either limx→∞f(x)=Llimx→∞f(x)=L or limx→−∞f(x)=Llimx→−∞f(x)=L, and LL is finite.

Calulate limits:

limx→∞(1x−2(−3x2+7x+1))=−∞

limx→−∞(1x−2(−3x2+7x+1))=∞

Thus, there are no horizontal asymptotes.

For Oblique Asymptote:

Do polynomial long division (−3x2+7x+1)/(x-2)=−3x+1+3/(x−2)

The rational term approaches 0 as the variable approaches infinity.

Thus, the slant asymptote is y=−3x+1y=−3x+1.

12z

Step-by-step explanation: