Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 9 when x is less than 0 and the absolute value of the quantity 2 minus x when x is greater than or equal to 0

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The limit does not exist.

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Ответ:

ivankerwin

04.01.2023

Mathematics

$\frac{8}{25}$ square miles

Step-by-step explanation:

The relationship between the side length (let it be s) of a square and its diagonal (let it be d) is given by:

$s=\frac{d}{\sqrt{2} }$

Since d is given as 4/5, we solve for s:

$s=\frac{d}{\sqrt{2} }\\s=\frac{\frac{4}{5}}{\sqrt{2} }\\s=\frac{4}{5\sqrt{2} }$

NOW, area of square is s^2 where s is the side length.

Area = $s^2=(\frac{4}{5\sqrt{2} })^2=\frac{16}{50}=\frac{8}{25}$

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Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 9 when x is less than 0 and the absolute value of the quantity 2 minus x when x is greater than or equal to 0 -9 -7 2 The limit does not exist.