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10crank78

05.10.2022

Mathematics

A group of k elements can be chosen from a group of n elements in $\frac{n!}{k!(n-k)!}$ ways.

$(^6 _4)=\frac{6!}{4!(6-4)!}=\frac{6!}{4! \times 2!}=\frac{4! \times 5 \times 6}{4! \times 2}=\frac{5 \times 6}{2}=5 \times 3=15$

A group of 4 people can be selected from a group of 6 people in 15 ways.

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