Find the largest number which divides 224,250 and 302 and leaves remainder 3 in each case.

To have a remainder 3, we take away 3 from each number first.

Take away 3:
224 - 3 = 221
250 - 3 = 247
302 - 3 = 299

Prime factorisation of each of the numbers:
221 = 13 x 17
247 = 13 x 19 
299 = 13 x 23

Find HCF:
HCF = 13

The largest number that can be divided is 13.

The answer would be three and four because adding the two opposite s together should equal zero.
Ex: (2 + - 2 = 0)
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