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michellemunoz250
09.10.2019 •
Mathematics
Find the lcd of the pair of expressions. 1/2; 4/x^2 a. 4x^2 b. 2x^2 c. 2x d.x^2 find the lcd of the pair of expressions. 8/5b; 12/7b^3c a. 7b^3c b. 12b^3c^2 c.35b^3c^2 d.35b^3c^2 find the lcd of the pair of expressions. 3m/m+n, 3n/m-n
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Ответ:
1/2 and 4/x²
The LCD is simply 2x²
The second pair of expressions is
8/5b and 12/7b
The LCD is simply
5(7)b = 35b
The last pair is
3m/m+n and 3n/m-n
The LCD is
(m + n)(m -n)
Ответ:
The numbers are: 1 and 3.
Step-by-step explanation:
Let the first number be
and the second number be
.
Given: The difference between twice the number and the second number is
. writing this mathematically,
From the second statement we get:
Solving for
and
we get:
and![$ y = 3 $](/tpl/images/0365/3992/25ac6.png)
Thus the first number is 1 and the second number is 3.