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emilystartk
20.01.2020 •
Mathematics
Find the linear approximation of the function
f(x) = sqrt of (1 − x) at a = 0. use l(x) to approximate the numbers sqrt of 0.9 and sqrt of 0.99.
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Ответ:
1−x−−−−√≈−12x+1
0.9−−−√=1−0.1−−−−−−√≈−12(0.1)+1
To simplify:
−1/2⋅1/100+1=−1/2⋅1/100+200/200=200−1/200=199/200 or =.995
So yes for sqrt (.99), that is a good approximation.
To write linear approximations:
Our curve should be y=f(x) and substitute x=a for the numbers m
Our formula for the linear equation is y=mx+b
So subtsitute
y′=f′(x)
y=f′(a)x+b
Then find the y-intercept, which is b.
Given: (a, f(a))= point of the line
Then substitute, that would be
f(a)=f′(a)⋅a+b
f(a)−f′(a)⋅a=b
So the tangent line to y=f(x) at x=a
Or the equation we will use for linear approximations is:
y=f′(a)x+f(a)−f′(a)⋅a
y=f′(a)⋅(x−a)+f(a)
Ответ:
Each time the number of hours (on the x axis) goes up by 1, the cost (on the y axis) goes up by up by $2. So each hour costs $2.
You can pick two points on the graph, such as (1,2) and (2,4) to compute the slope using the slope formula below
m = (y2 - y1)/(x2 - x1)
m = (4-2)/(2-1)
m = 2/1
m = 2 we get a slope of 2
The slope is the rise/run
rise = change in cost = change in y
run = change in time = change in x