Find the maximum height of the rocket and explain in at least threes sentence how you calculated your answer of y = - 16x ^ 2 + 480x

The maximum height of the rocket is 3600

Step-by-step explanation:

The vertex of the quadratic equation y = ax² + bx + c is (h, k), where

h = k = y at x = hThe vertex (h, k) is a minimum point if a is positive  The vertex (h, k) is a maximum point if a is negative

The height of the rocket calculated using the equation y = -16x² + 480x, where y is the height and x is the time

To find the maximum height, do that

Find the x-coordinate of the vertex of the equation ⇒ hSubstitute the value of x in the equation by h to find the y-coordinate of the equation ⇒ kThe maximum height equal the value of k

Let us do that

∵ y = -16x² + 480x

∴ a = -16 ⇒ the vertex is a maximum point

∴ b = 480

→ Use the rule above to find h

∵ h =

∴ h = =

∴ h = 15

∵ k = y at x = h

→ Substitute x by 15 in the equatuion and y by k to find x

∵ k = -16(15)² + 480(15)

∴ k = -3600 + 7200

∴ k = 3600

∵ The maximum height equal the value of k

∴ The maximum height of the rocket is 3600

You have to have x by itself for this equation and to solve x.
-9x+1=-1x+17
We’re going to add 1x to each side.
-8x+1=17
Now we’re going to subtract 1 to each side.
-8x=16
We have to divide each side by -8 so we can get x by itself.
16/-8=-2=x
So b, x equals -2.