Mathematics: Find the perimeter of a rectangle l= 2x^2+3x+1 w= x+3

Find the perimeter of a rectangle l= 2x^2+3x+1

cordobamariana07

09.01.2022

The perimeter of the rectangle is $P(x) = (4x^{2} + 8x + 8)$

Step-by-step explanation:

Length of the rectangle = $2x^{2} +3x + 1$

Width of the rectangle = x + 3

The Perimeter of the Rectangle = 2 (Length + Width)

So, here the perimeter = $2((2x^{2} + 3x +1 )+(x+3)) = 2 (2x^{2} + 3x + 1 + x +3)\\= 2(2x^{2} + 4x+4) = 4x^{2} + 8x + 8$

Hence,the perimeter of the rectangle is $P(x) = (4x^{2} + 8x + 8)$

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jaaiphieaslade

29.06.2022

answer: 21

step-by-step explanation: 20+1

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