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darkghostmist
31.05.2021 •
Mathematics
Find the period of an electromagnetic wave of wavelength 2.20 × 10–2 m. A. 1.36 × 1010 s c. 7.33 × 10–11 s b. 4.54 × 101 s d. 6.60 × 106 s
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Ответ:
7.33 * 10^-11 s
Step-by-step explanation:
Period, T = 1 / f
c = fλ
λ = 2.20 × 10^–2 m
c = speed of light = 3 * 10^8 m
f = c / λ
f = 3 * 10^8 ÷ 2.20 × 10^–2 m
f = (3/2.2) * 10^(8-(-2))
f = 1.364 * 10^10
T = 1/f
T = 1 / 1.364 * 10^10
T = 7.33 * 10^-11 s
Ответ: