Find the probability: not spinning a 4 and flipping tails

Define the events
A = spinning any number but 4 (ie not getting 4)
B = flipping tails

For each event, the probabilities are:
P(A) = 4/5 because there are four numbers that aren't "4" out of five numbers total
P(B) = 1/2 assuming the coin is fair and each side is likely

P(A and B) = P(A)*P(B) is possible because the two events A and B are independent

So,
P(A and B) = P(A)*P(B)
P(A and B) = (4/5)*(1/2)
P(A and B) = (4*1)/(5*2)
P(A and B) = 4/10
P(A and B) = 2/5

The answer as a fraction is 2/5
In decimal form, the answer is 0.4

7(x + 4) = 9(x - 2)
7x + 28 = 9x - 18
28 + 18 = 9x - 7x
46 = 2x
46/2 = x
23 = x <===