Find the probability of rolling a three first and then a ten when a pair of dice is rolled twice

1/216

Step-by-step explanation:

When a pair of dice is rolled, there are 36 possible different outcomes.

Of those 36 different outcomes, a sum of 3 is obtained in 2 different ways: 1, 2 and 2, 1.

Of those 36 different outcomes, a sum of 10 is possible in 3 different ways: 6, 4; 5, 5; 4, 6.

p(3 followed by 10) = p(3) * p(10) = 2/36 * 3/36 = 1/18 * 1/12 = 1/216

A) Divide and compare in decimal form -
9/25 = 0.36
4/6=2/7 = 1/4 = 0.25
0.6... > 0.25

B) Fraction to decimal conversion:
4/16 = 2/8 = 1/4 = 0.25

Use long decision or a calculator - 1 divided by four

C) Again, 9/25 = nine divided by twenty-five = 0.36

% Science class)

0.36 = 36%
Move decimal place to right twice and place “%” at the end.