Mathematics: Find the radius of (x-3)^2+(y+5)^2=49

Find the radius of (x-3)^2+(y+5)^2=49 - id3252491271626, nestergurl101

Ответ:

gleatons429

14.03.2022

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x-3)^2+(y+5)^2=49\implies [x-\stackrel{h}{3}]^2+[y-\stackrel{k}{(-5)}]^2=\stackrel{r}{7^2}\qquad r=7$

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Ответ:

ctyrector

17.02.2020

Mathematics

well its non proportional thats for sure and i believe its an example of strong because the start of ten going greater is strong but if it was gooing down to maybe negatives it would be weak correlation

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Find the radius of (x-3)^2+(y+5)^2=49

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