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branj1317
21.07.2019 •
Mathematics
Find the real-valued solution to the initial value problem {y′1y′2==−3y1−2y2,5y1+3y2,y1(0)=3,y2(0)=−10. {y1′=−3y1−2y2,y1(0)=3,y2′=5y1+3y2,y2(0)=−10. use tt as the independent variable in your answers.
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Ответ:
Then:
The eigenvectors are as follows:
Therefore, the solution is given as follows:
Thus, the solution is given by:
Applying the initial condition, we have
Therefore, the solution to the initial value problem is:
Ответ:
Step-by-step explanation:
4x^2+120x
4x^2+120x=0
4x^2=-120x
4x^2/x=-120
4x=-120
x=-120/4
x=-30