violetagamez2
05.10.2021 •
Mathematics
Find the remainder when 9²-fix 2 is divided by 1-3 (x+3 (i) 3x+1 (0) 1SolutionLet p(x) = 9x ^ 2 - 6x + 2 When p(x) is divided by x-3, by Remainder Theorem, the remainder isR=P(3)=9(3)³-6(3)+2=65When p(x) is divided by x + 3 = x - (- 3) , the remainder isR=(-3)=9(-3)²-6(-3)+2=101 When pix) is divided by 3x+1, the remainder isWhen p(x) is divided by 1, the remainder is R =p(0)=9(0)³-6(0)+2=2
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Ответ:
equal angles
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