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26.02.2020 •
Mathematics
Find the second derivative at the point (1,1), given the function below. 2x^9+1=3y^3
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Ответ:
The value at point ( 1, 1 ) is 8.
Explanation:
Given
3y³ = 2x⁹ + 1
y³ = 2/3x⁹ + 1/3
y = ∛2/3 x⁹ + 1/3
We need to first find dy/dx which is the first derivative and then d²y/dx² which is the second derivative
Put the value of (1,1) : x = 1 and y = 1 in d²y/dx² equation
Therefore, the value is 8.
Ответ:
4. 5
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