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27.02.2021 •
Mathematics
Find the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6).
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Ответ:
y=-3x+6
Step-by-step explanation:
x-3y=5
y=1/3x-5/3
slope of perpendicular line is -3 (opposite reciprocals)
y=mx+b
x=0 and y=6
6=3x+b
6=3(0)+b
6=b
y=-3x+6
Ответ: