Find the slope of the line through the given points.
(-3,-18) and (1,2)

5

Step-by-step explanation:

Slope (m) =

ΔY

ΔX

=

5

1

=5

θ =

arctan(ΔY)

ΔX

=78.69006752598°

ΔX = 1 – -3 = 4

ΔY = 2 – -18 = 20

Distance (d) = √ΔX2 + ΔY2 = √416 = 20.396078054371

Equation of the line:

y = 5x – 3

When x=0, y = -3

When y=0, x = 0.6

First set up a system of equations and solve.

4x+y=10
x+3y=8
In order to have one variable cancel out, I will multiply the top by -3.

-12x-3y=-30
x+3y=8

-11x=-22
x=2

Then plug the x value into one of the original equations.

(2)+3y=8
3y=6
y=2

Now plug both into the final equation:
5(2)+8(2)/3
(10+16)/3
26/3
8.667 is the answer or 26/3.