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lorielle
14.11.2021 •
Mathematics
Find the Solution in the Interval [0,2 pi]
tan(theta/7)+ square root3= 0
Solved
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Ответ:
9514 1404 393
no solution
Step-by-step explanation:
The solutions to the equation are ...
tan(θ/7) +√3 = 0
tan(θ/7) = -√3
θ/7 = arctan(-√3) +nπ . . . . . . . for integer n
θ = 7(-π/3 +nπ) = 7π(n -1/3)
For n=0, θ = -7π/3 -- not in the required interval.
For n=1, θ = 14π/3 -- not in the required interval.
There are no solutions in the required interval.
Ответ:
-14
Step-by-step explanation:
4n - 6 , n= -2
= 4* (-2) - 6
= -8 -6
= - 14