Find the solution of and determine if it is an extraneous

Ответ:

ABrabbit732

03.01.2022

x = 14 is an extraneous solution

Step-by-step explanation:

$4\sqrt{x + 2} = -16$

Divide both sides by 4.

$\sqrt{x + 2} = -4$

Square both sides.

$(\sqrt{x + 2})^2 = (-4)^2$

x + 2 = 16

x = 14

Since we squared both sides, we much check for extraneous solutions because the process of squaring both sides can introduce extraneous solutions.

Check x = 14:

$4\sqrt{x + 2} = -16$

$4\sqrt{14 + 2} = -16$

$4\sqrt{16} = -16$

4(4) = -16

16 = -16

16 = -16 is a false statement, so the solution we found, x = 14, is an extraneous solution.

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carechiga24

09.11.2022

EW!!

Step-by-step explanation:

SEARCH UP V*GINA AND WATCH VIDEOS

BTW(THE PERSON WHO ALSO ANSWERED WAS WRONG)

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