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27.07.2019 •
Mathematics
Find the solution of this system of equations 3x+2y= -21 -7x-4y=33
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Ответ:
i) 3x+2y=-21
ii) -7x-4y=33.
We notice that we can eliminate the y's by multiplying the first equation by 2, and adding this equation to the second one, as follows:
multiplying equation (i) by 2 we have
i) 6x+4y=-42
ii) -7x-4y=33.
Adding these equations side by side, we get:
6x-7x=-42+33, which simplifies to -x=-9, thus x=9.
Since 3x+2y=-21, substituting x=9, we can find y:
3(9)+2y=-21
27+2y=-21
2y=-21-27
2y=-48
thus y=-28/2=-24.
The solution of the system is (x,y)=(9, -24).
Ответ:
3x + 2y = -21
This can be rewritten as:
2y = -21 - 3x > equation I
The second given equation is:
-7x - 4y = 33
This can be rewritten as:
-7x - 2(2y) = 33 > equation II
Substitute with equation I in equation II to get the value of x as follows:
-7x - 2(2y) = 33
-7x -2(-21-3x) = 33
-7x + 42 + 6x = 33
-x = 33-42 = -9
x = 9
Substitute with the value of x in equation I to get the value of y as follows:
2y = -21 - 3x
2y = -21 -3(9)
2y = -21-27 = -48
y = -24
Based on the above calculations:
x - 9
y = -24
Ответ:
They are being multiplied by 2 each time
Step-by-step explanation:
2x2=4 4x2=8 8x2=16 16x2=32