Mathematics: Find the solution to the system of equations. x - 2y - z= -2 x+2y+ z= 0 y+ 3z = 3 a. x=-1, y = 0, z = 3 b. x= -1, y=-1, z = 0 c.x=-1, y=1, z= 1 d. x=-1, y= 0, z = 1

Find the solution to the system of equations. x

Ответ:

jacob12049

07.01.2022

=> D

X-2y-z=-2
X+2y+z=0
Y+3z=3

2x=-2
X=-1

(-1)+2y+z=0
2y+z=1
Z=-2y+1

Y+3(-2y+1)=3
Y-6Y+3=3
-5y=0
Y=0

Y+3z=3
0+3z=3
Z=1

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Ответ:

liliauedt

22.09.2022

Mathematics

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{15})\qquad
(\stackrel{x_2}{9}~,~\stackrel{y_2}{-18})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-18-15}{9-(-2)}\implies \cfrac{-33}{9+2}\implies \cfrac{-33}{11}\implies -3
\\\\\\
\begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-15=-3[x-(-2)]\implies y-15=-3(x+2)
\\\\\\
y-15=-3x-6\implies y=-3x+9$

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Find the solution to the system of equations.
x - 2y - z= -2
x+2y+
z= 0
y+ 3z = 3
a. x=-1, y = 0, z = 3
b. x= -1, y=-1, z = 0
c.x=-1, y=1, z= 1
d. x=-1, y= 0, z = 1

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