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javontiye226
29.10.2019 •
Mathematics
Find the sum of all coefficients in the following binomial expansion.
a. (2u + v)^10
b. (2u − v)^10
c. (2u − 3v)^11
d. (u − 3v)^11
e. (1 + i)^10
f. (1 − i)^10
g. (1 + i)^200
h. (1 + i)^201
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Ответ:
We can find the sum of all the coefficients by substituting all the variables in the expansion with one.
a. u=1,v=1
sum=
=![3^{10}](/tpl/images/0350/5884/a5bb2.png)
b.u=1,v=1
sum=
=1
c.u=1,v=1
sum=
=-1
d.u=1,v=1
sum=
=-![2^{11](/tpl/images/0350/5884/51ce4.png)
e.i=1
sum=
=![2^{10](/tpl/images/0350/5884/6ca22.png)
f.i=1
sum=
=0
g.i=1
sum=
=![2^{200](/tpl/images/0350/5884/61374.png)
h.i=1
sum=
=![2^{201](/tpl/images/0350/5884/7a869.png)
Ответ:
To solve this, we can use the slope given two points formula:
y2-y1/x2-x1
This formula calculates the slope of the line created by two given points. Let's plug in (0,1) and (1,3):
3-1/1-0 = 2/1 = 2
Therefore, the slope is 2.
For the next pair (1,2) and (2,4):
4-2/2-1 = 2/1 = 2
Thus, both slopes are 2.
Hope this helps!