Mathematics: Find the sum of the first fifteen terms of the series: 3+6+12+24+... PLZZZ HELP ONLY RIGHT ANSWER

Find the sum of the first fifteen terms of the series:

artursino

21.01.2022

The sum of the first fifteen terms of the series is 98303

Explanation:

Given that the series is 3,6,12,24,.....

We need to determine the sum of the first terms of the series.

Common difference (r):

$r=\frac{6}{3} =2$

Hence, the common difference between is 2

The sum of the series can be determined using the formula,

$S_{n}=\frac{a_{1}\left(r^{n}-1\right)}{r-1}$

Substituting a_1=3 , n=15 and r=2 , we get,

$S_{15}= \frac{3(2)^{15}-1}{2-1}$

Hence, simplifying the terms, we get,

$S_{15}= \frac{3(32768)-1}{2-1}$

$S_{15}= \frac{98304-1}{1}$

$S_{15}= 98303$

Thus, the sum of the first fifteen terms of the series is 98303

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nofer

21.10.2021

Step-by-step explanation:

2/3 ÷ 1/6 =

2/3 x 6/1 =

12/3 = 4

Also you can do:

2/3 = 4/6

there are 4- 1/6 in 4/6

If my answer is incorrect, pls correct me!

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-Chetan K

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