Find the sum of the given vectors and illustrate geometrically. [-1,4],[6,-2]

The sum of vectors is <5,2>.

Step-by-step explanation:

The given vectors are <-1,4> and <6,-2>.

We need to find the sum of the given vectors and illustrate geometrically.

Plot the point (-1,4) on a coordinate plane and draw a vector <a> from (0,0) to (-1,4).

Plot the point (6,-2) on a coordinate plane and draw a vector <b> from (0,0) to (6,-2).

Now complete the parallelogram and the diagonal represents the sum of both vectors.

The end point of the diagonal is (5,2). It means sum of vectors is <5,2>.

Check the sum of vectors:

Therefore, the sum of vectors is <5,2>.

To solve this problem you must apply the proccedure shown below:
 1. The problem asks for the area of a cross section that is parallel to face ABCD. As is parallel to that face, you have can calculate its area as following:
 A=12 cm x 6 cm
 2. Therefore, the result is:
 A=72 cm²
 The answer is: The area of a cross section that is parallel to face ABCD is 72 cm².