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tmark45
26.08.2020 •
Mathematics
Find the sum to infinity of a geometric series having a second term of -9 and fifth term of 1/3 g
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Ответ:
S infinity= -51/4
Step-by-step explanation:
First term
ar= -9
Fifth term
ar⁴= 1/3
Solving for the value of the r and a
ar= -9
ar⁴= 1/3
Dividing each other
r³=1/3 * -1/9
r³=-1/27
r= 3√-1/27
r= -1/3
Solving for a
ar= -9
a(-1/3)= 9
a= 9*-3
a= -27
Sum of a go to infinity is given by the formula
S infinity= a/(1-r)
S infinity= -27/(1-(-1/3))
S infinity= -27/(1+1/3)
S infinity= -27 * 3/4
S infinity= -51/4
Ответ:
In this case, dr/dθ is the derivative of the function r which is equal to -cos (theta/2) * sin (theta/2) which is equal to -1/2 cos theta. Since there are no limits defined, we leave the formula as it is but one can use the calculator if there are limits present already