![gretchcampbell](/avatars/49617.jpg)
gretchcampbell
21.10.2020 •
Mathematics
Find the value of a in the relation Cov(2X,−3Y+2)=a⋅Cov(X,Y) .
a=
c) Suppose that X , Y , and Z are independent, with a common variance of 5 . Then,
Cov(2X+Y,3X−4Z)=
Solved
Show answers
More tips
- S Style and Beauty How to Choose the Perfect Hair Straightener?...
- F Family and Home Why Having Pets at Home is Good for Your Health...
- H Health and Medicine How to perform artificial respiration?...
- H Health and Medicine 10 Tips for Avoiding Vitamin Deficiency...
- F Food and Cooking How to Properly Cook Buckwheat?...
- F Food and Cooking How Many Grams Are In a Tablespoon?...
- L Leisure and Entertainment Carving: History and Techniques for Creating Vegetable and Fruit Decorations...
- P Photography and Videography How to Choose the Perfect Photo Paper for Your Images?...
- H Health and Medicine What vaccines do children need?...
- H Health and Medicine Reasons for the Appearance of Warts: Everything You Need to Know...
Answers on questions: Mathematics
- M Mathematics Which of the following is an example of an aerobic activity that improves cardiovascular endurance? a. step aerobics b. weight lifting c. yoga d. breathing exercises...
- M Mathematics Asurvey found that women s heights are normally distributed with mean 63.6 in. and standard deviation 3.7 in. the survey also found that men s heights are normally distributed...
- M Mathematics Which of the following is the surface area of the right cylinder below? O A. 2247 units2 O B. 20477 units O C. 3527 units O D. 8967 units...
- S SAT Identify each example as an ethnic boundary marker, or not....
- M Mathematics 4x^2+5=8x what is the answer in standard form...
Ответ:
a = -6
Cov (2X+Y, 3X-4Z) = 30
Step-by-step explanation:
Key points:
Cov (aX, bY) = a·b·Cov (X, Y)Cov (X, X) = V (X) Cov (X, a) = 0If X and Y are independent then Cov (X, Y) = 0.Cov(2X, -3Y+2) = a⋅Cov (X,Y)
Cov (2X, -3Y) + Cov (2X, 2) = a⋅Cov (X,Y)
(2)⋅(-3)⋅Cov (X, Y) + 0 = a⋅Cov (X,Y)
-6⋅Cov (X, Y) + 0 = a⋅Cov (X,Y)
⇒ a = -6.
(c)
Suppose that X, Y, and Z are independent, with a common variance of 5, i.e. V (X) = V (Y) = V (Z) = 5
Cov (2X+Y, 3X-4Z) = Cov (2X, 3X) + Cov (2X, -4Z) + Cov (Y, 3X) + Cov (Y, -4Z)
= 6⋅Cov (X, X) - 8⋅Cov (X, Z) + 3⋅Cov (Y, X) - 4⋅Cov (Y, Z)
= (6 × 5) - 0 + 0 - 0
= 30
Thus, the value of Cov (2X+Y, 3X-4Z) is 30.
Ответ: