OrionGaming
17.01.2020 •
Mathematics
Find the value of k such that kx^2+12x-4=0 has one real number solution. explain
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Ответ:
+4 +4
kx^2+12x=-4
-12x -12x
kx^2=-4-12x
square root kx^2 to get kx and square root -4-12x too
kx=the square root of -4-12x
then divide x to both sides and u get ur answer
Ответ:
+4 +4
kx^2+12x=-4
-12x -12x
kx^2=-4-12x
square root kx^2 to get kx and square root -4-12x too
kx=the square root of -4-12x
then divide x to both sides and u get your answer
X=-3
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Ответ:
7 bowls
Step-by-step explanation:
5_ 5/6 divided by 3/4 equals 7.77777