Find the value of the term in the arithmetic sequence using an = a^1+ (n-1)d. 3,5,7,9,11, (8th term)

Work Shown:

a1 = 3 = first term

d = 2 = common difference (since we add 2 to each term to get the next one)

Let's compute the nth term.

an = a1 + (n-1)*d

an = 3 + (n-1)*2

an = 3 + 2n-2

an = 2n+1

To check things so far, we can plug in something like n = 2

an = 2n+1

a2 = 2*2+1

a2 = 5

Showing that the 2nd term is 5, which matches with the sequence given to us

Let's check n = 3

an = 2n+1

a3 = 2*3+1

a3 = 7

That matches as well. I'll let you check the others.

Plug in n = 8 to find the 8th term

an = 2n+1

a8 = 2*8+1

a8 = 17

The eighth term is 17, which is the final answer.

You could extend out the given sequence by adding 2 each time until you reach the 8th term

3,5,7,9,11,13,15,17

Though this method is slow if you need to find say the 38th term

17 is the answer for the value of the term in the arithmetic sequence using the above

B or 31r-71

Step-by-step explanation:

First, use distributive property to expand the first term.

30r-66-(5-r)

Remove the parenthesis of the third term:

30r-66-5+r

Combine like terms

31r-71