Mathematics: find the values of x that would make the area of the rectangle greater than the area of the triangle.can you help me pls

find the values of x that would make the area of

Ответ:

kiarrafryer

13.02.2022

Step-by-step explanation:

$The\ area\ of\ the\ rectangle\ in\ terms\ of\ x=6x\\The\ area\ of\ the\ triangle\ in\ terms\ of\ x=\frac{4(x+6)}{2}=2(x+6) \\Given\ condition:\\The\ area\ of\ the\ rectangleThe\ area\ of\ the\ triangle\\Hence,\\6x2(x+6)\\Now, as\ practically\ any\ of\ the\ side\ of\ the\ polygons\ cannot\ be\ negative.\\\\Hence,\\6x2x+12\\6x-2x2x+12-2x\\4x12\\\frac{4x}{4} \frac{12}{4} \\x3$

$Hence,\\x\ could\ be\ any\ real\ number\ greater\ than\ 3.$

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Ответ:

heleneallie7ou1fnk

05.04.2022

Mathematics

23)

2(5-3x)<x-4(3-x)

distribute 2 to 5 then 2 to 3x and get 10 - 6x then go on the right side and distribute the -4 to the 3 = -12 cancel out both x since one is negative and ones positive. which is 10 - 6x < -12

subtract 10 on each side and divide by 2

10-10= 0 -12 - 10= 22 divide by 2 is 11 x=11 do that with the other one also

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find the values of x that would make the area of the rectangle greater than the area of the triangle.can you help me pls

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