Mathematics: What is the answer to this problem? 2(-7+x) -2

a) For we have the following valueAnd the relative change would be given by:And replacing we got:b) For we have the following valueAnd the relative change would be given by:And replacing we got:c) For we have the following valueAnd the relative change would be given by:And replacing we got:Step-by-step explanation:For this case we have the following function given:Where t represent the number of months since January of 2014Part aFor this case we have the initial time at January 2014 and that represent...

What is the answer to this problem? 2(-7+x) -2

Ответ:

littlepotato10

15.03.2020

Mathematics

a) $B(15)= 29.05 e^{0.0214 *15}= 40.046$

For $\Delta t = 1$ we have the following value

$B(t+ \Delta t) = B(15+1) = B(16) = 29.05 e^{0.0214 *16}= 40.912$

And the relative change would be given by:

$\frac{B(16) - B(15)}{B(15)}$

And replacing we got:

$\frac{40.912-40.046}{40.046}= 0.0216 = \approx 2.16 \%$

b) $B(15)= 29.05 e^{0.0214 *15}= 40.046$

For $\Delta t =0.1$ we have the following value

$B(t+ \Delta t) = B(15+0.1) = B(15.1) = 29.05 e^{0.0214 *15.1}=40.131$

And the relative change would be given by:

$\frac{B(15.1) - B(15)}{B(15)}$

And replacing we got:

$\frac{40.131-40.046}{40.046}= 0.00214 = \approx 0.214 \%$

c) $B(15)= 29.05 e^{0.0214 *15}= 40.046$

For $\Delta t =0.1$ we have the following value

$B(t+ \Delta t) = B(15+0.01) = B(15.01) = 29.05 e^{0.0214 *15.1}=40.054$

And the relative change would be given by:

$\frac{B(15.01) - B(15)}{B(15)}$

And replacing we got:

$\frac{40.054-40.046}{40.046}= 0.000214 = \approx 0.0214 \%$

Step-by-step explanation:

For this case we have the following function given:

$B(t) = 29.05 e^{0.0214 t}$

Where t represent the number of months since January of 2014

Part a

For this case we have the initial time at January 2014 and that represent the value of t =0.

For march of 2015 the value fo t would be t = 15

We can estimate the corresponding value of B(15) and we got:

$B(15)= 29.05 e^{0.0214 *15}= 40.046$

For $\Delta t = 1$ we have the following value

$B(t+ \Delta t) = B(15+1) = B(16) = 29.05 e^{0.0214 *16}= 40.912$

And the relative change would be given by:

$\frac{B(16) - B(15)}{B(15)}$

And replacing we got:

$\frac{40.912-40.046}{40.046}= 0.0216 = \approx 2.16 \%$

Part b

For this case we have the initial time at January 2014 and that represent the value of t =0.

For march of 2015 the value fo t would be t = 15

We can estimate the corresponding value of B(15) and we got:

$B(15)= 29.05 e^{0.0214 *15}= 40.046$

For $\Delta t =0.1$ we have the following value

$B(t+ \Delta t) = B(15+0.1) = B(15.1) = 29.05 e^{0.0214 *15.1}=40.131$

And the relative change would be given by:

$\frac{B(15.1) - B(15)}{B(15)}$

And replacing we got:

$\frac{40.131-40.046}{40.046}= 0.00214 = \approx 0.214 \%$

Part c

For this case we have the initial time at January 2014 and that represent the value of t =0.

For march of 2015 the value fo t would be t = 15

We can estimate the corresponding value of B(15) and we got:

$B(15)= 29.05 e^{0.0214 *15}= 40.046$

For $\Delta t =0.1$ we have the following value

$B(t+ \Delta t) = B(15+0.01) = B(15.01) = 29.05 e^{0.0214 *15.1}=40.054$

And the relative change would be given by:

$\frac{B(15.01) - B(15)}{B(15)}$

And replacing we got:

$\frac{40.054-40.046}{40.046}= 0.000214 = \approx 0.0214 \%$

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2(-7+x)> -2

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