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alyssams1213
02.01.2020 •
Mathematics
Find the vertex and the y-intercept of the graph of y = 2x^2 + 16x + 33.
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Ответ:
see explanation
Step-by-step explanation:
Given a quadratic in standard form : ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
y = 2x² + 16x + 33 ← is in standard form
with a = 2, b = 16, c = 33, hence
Substitute x = - 4 into the equation for y- coordinate of vertex
y = 2(- 4)² + 16(- 4) + 33 = 32 - 64 + 33 = 1
vertex = (- 4, 1 )
To find the y- intercept substitute x = 0 into the equation
y- intercept = 2(0)² + 16(0) + 33 = 0 + 0 + 33 = 33
Ответ:
I'm great actually I almost thought I had a bad grade in Spanish