Mathematics: Find the vertex of parabola y=-2x^2-20x-48

Find the vertex of parabola y=-2x^2-20x-48 - id2220483577619, clairajogriggsk

Ответ:

nikki225

27.11.2021

Mathematics

part a) draw two triangles, translating one of them to the right.

part b) Consider triangles ΔYXB and ΔYZA. In these triangles:

∠Y is common, then ∠XYB≅∠ZYA (additional information that is needed);∠YXB≅∠YZA (given);XY≅ZY (given).

Therefore, these two triangles have two congruent angles adjacent to congruent sides. By the ASA Postulate, ΔYXB≅ΔYZA.

ASA Postulate: If two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the triangles are congruent.

part c) flow chart proof:

$\triangle YXB\cong \triangle YZA\Rightarrow$

XY≅ZY (given);XB≅ZA (implies);YB≅YA (implies).

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Find the vertex of parabola y=-2x^2-20x-48

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