Find the volume of a cone with base area 36π ft2 and a height equal to twice the radius. Give your answers both in terms of π and rounded to the nearest tenth.
The volume in terms of π is ft3.
The volume rounded to the nearest tenth is ft3.

The volume in terms of π is 144 ft³

The volume rounded to the nearest tenth is 452.4 ft³

Step-by-step explanation:

The formula of the volume of a cone is V = π r² h , where r is its radius and h is its height

The formula of the area of a circle is A = π r²

∵ The area of the base of the cone is 36π ft²

- Equate the formula of the area of the circle by 36π to find r

∵ πr² = 36π

- Divide both sides by π

∴ r² = 36

- Take √ to both sides

∴ r = 6 ft

∵ The height of the cone is equal to twice the radius

∵ The radius of the cone is 6 ft

- Multiply 6 by 2 to find the height

∴ h = 2(6) = 12 ft

∴ The height of the cone is 12 ft

Substitute the values of h and r in the formula of the volume of the cone to find it

∵ V = π(6)²(12)

∴ V = 144 π ft³

∴ V = 452.3893421 ft³

- Round it to the nearest tenth

∴ V = 452.4 ft³

mid point (x,y) = M (18, 24)

let J (- 4, - 2) be ( x1, y1)

     L(a,b) be (x2,y2)

using midpoint formula

(x,y) = [(x1+x2)/2, (y1 + y2)/2]

or, (18, 24) = [(-4+a)/2, (-2+b)/2]

comparing corresponding element we get

18 = (-4+a)/2                 24 =(-2+b)/2

or 36 = -4+ a            or 48 = -2 +b

or a = 40                  or b= 50

L(40,50)