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dmgboos6
22.06.2019 •
Mathematics
Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. y = (7x + 6)^(-1/2) y = 0 x = 0 x = 4
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Ответ:
V = .779 (that's with pi multiplied in)
Step-by-step explanation:
We will use the disk method here with a vertical representative rectangle. With this method, we use y = x equations and x intervals. The height of the rectangle is the curve itself, and since there is no space between the solid and the axis of revolution, the integral looks like this:
When you square a square root it's eliminated, so we simply have:
Now we integrate. This pattern follows that of the natural log. Identify the "u" we need and take it from there.
u = 7x + 6
du = 7 dx and, finally,
Filling in our bounds applying the First Fundamental Theorem of Calculus:
Ответ:
(5 – 7)2
Step-by-step explanation:
(5 – 7)2 equals 4