Mathematics: Find the zeros of f(x)=3x^3+2x^2-12x-8

Find the zeros of f(x)=3x^3+2x^2-12x-8 - id3322128517102, kingdevin16

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gg68814

11.03.2022

$f(x)=3x^3+2x^2-12x-8\\\\f(x)=0\iff3x^3+2x^2-12x-8=0\\\\x^2(3x+2)-4(3x+2)=0\\\\(3x+2)(x^2-4)=0\iff3x+2=0\ \vee\ x^2-4=0\\\\3x+2=0\qquad|-2\\\\3x=-2\qquad|:3\\\\\boxed{x=-\dfrac{2}{3}}\\\\x^2-4\qquad|+4\\\\x^2=4\to x=\pm\sqrt4\\\\\boxed{x-2}\ \vee\ \boxed{x=2}\\\\\ x=-2,\ x=-\dfrac{2}{3}\ or\ x=2.$

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Ответ:

zymikaa00

25.12.2021

Mathematics

The answer is C.y=2x. Hope this will help.

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Find the zeros of f(x)=3x^3+2x^2-12x-8

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