Find the zeros of quadratic equation X^2 - 3x + 9 = 5x - 10

x^2 - 3x + 9 - 5x + 10 = 0

x^2 - 8x + 19 = 0

Part A: -(2x - 3)(8x + 1)

Part B: (-0.125, 0), (1.5, 0)

Part C: As x goes to infinity, f(x) goes to negative infinity. As x goes to negative infinity, f(x) goes to negative infinity.

Part D: I would find the zeroes and the vertex and draw the graph.

Step-by-step explanation:

For Part A, simply just factor the quadratic and you should get -(2x - 3)(8x + 1).

For Part B, use a graphing calculator and find where the graph crosses the x-axis. Where is does cross is where your zeros are.

For Part C, simply see what the values go to when we go to either infinity or negative infinity. Since the graph is a parabola goes down, we go to negative infinity.

For Part D, you only need 3 vital points to graph: The zeros and the vertex. Find those and you should be able to graph. Alternatively, you could use a graphing calc.