Mathematics: Find the zeros of the function in the interval of [-2pi,2pi] f(x)=1/2cos2x

Find the zeros of the function in the interval

Ответ:

Madisonk3571

14.01.2022

$\dfrac12\cos2x=0\implies\cos2x=0$

Since the cosine is zero when the angle is an odd multiple of $\dfrac\pi2$ , you have $2x=\pm\dfrac\pi2,\pm\dfrac{3\pi}2,\pm\dfrac{5\pi}2,\pm\dfrac{7\pi}2$ .

Divide both sides by 2 and you get $x=\pm\dfrac\pi4,\pm\dfrac{3\pi}4,\pm\dfrac{5\pi}4,\pm\dfrac{7\pi}4$

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Ответ:

brae72

15.01.2020

Mathematics

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Find the zeros of the function in the interval of [-2pi,2pi]
f(x)=1/2cos2x

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