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robert7248
16.08.2021 •
Mathematics
Find three consecutive even integers so that twice the largest is 20 less than the sum of all three
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Ответ:
If x is the smallest of the three, then the next two integers are x + 2 and x + 4.
"Twice the largest is 20 less than the sum of all three" translates to
2 (x + 4) = (x + (x + 4) + (x + 6)) - 20
Solve for x :
2x + 8 = 3x - 10
x = 18
Then the three numbers are {18, 20, 22}.
Ответ:
look below
Step-by-step explanation:Let x, x+2 & x+4 be the 3 integers.
x+2(x+2)=(x+4)+20
x+2x+4=x+4+20
3x+4=x+24
3x-x=24-4
2x=20
Ответ:
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