kipper5760
23.11.2019 •
Mathematics
Find two consecutive odd integers such that 87 more than the lesser is six times the greater.
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Ответ:
The two integers are 15 and 17 .
Step-by-step explanation:
Given as :
The two odd integers as , 87 more than the lesser is six times the greater
Let The first integer = x
And The second integer = x + 2
Now, According to question
First integer + 87 = 6 times ( x + 2 )
I.e x + 87 = 6 × ( x + 2 )
Or, x + 87 = 6 x + 12
or, 87 - 12 = 6 x - x
or, 75 = 5 x
Or, 5 x = 75
∴ x =
I.e x = 15
So, The first integer = x = 15
And The second integer = x + 2 = 15 + 2 = 17
Hence The two integers are 15 and 17 . Answer
Ответ:
I think d is the answer