Find x, if 3x − 5(y + x ) ^2 = 16 and 4x + 2(y + x )^ 2 = 30

x is 7

Step-by-step explanation:

3x - 5(y + x)^2 = 16

3x - 16 = 5(y + x)^2

(y + x)^2 = 1/5(3x - 16) eqn(I)

4x + 2(y + x)^2 = 30

2(y + x)^2 = 30 - 4x

(y + x)^2 = 1/2(30 - 4x) eqn(II)

Equate eqn (I) & (II)

1/5(3x - 16) = 1/2(30 - 4x)

Multiply both sides by 10

2(3x - 16) = 5(30 - 4x)

6x - 32 = 150 - 20x

6x + 20x = 150 + 32

26x = 182

x = 182/26 = 7

lol this isn't tind.er

Step-by-step explanation:

NO