Find zeroes and multiplicity for y=(2x +3)(x -1)^2

zeros : -3/2 , multiplicity = 1

1 , multiplicity = 2

Step-by-step explanation:

To find zeros we set each factor =0  and solve for x

2x+3 =0

subtract 3 on both sides

2x= -3

divide by 2 on both sides

x= -3/2

The exponent of (2x+3) is 1 so multiplicity =1

Now we set (x-1)^2 =0

take square root on both sides

x-1 =0

add 1 on both sides

x=1

For (x-1)^2  the exponent is 2

So multiplicity = 2