First calculate the Subsets for set, then calculate the number of proper subsets {10,19,5,0}

The subsets of {10, 19, 5, 0} are

{ } - the empty set, or 1 subset of size 0

{10}, {19}, {5}, {0} - 4 subsets of size 1

{10, 19}, {10, 5}, {10, 0}, {19, 5}, {19, 0}, {5, 0} - 6 subsets of size 2

{10, 19, 5}, {10, 19, 0}, {10, 5, 0}, {19, 5, 0} - 4 subsets of size 3

{10, 19, 5, 0} - 1 subset of size 4

A proper subset of a set is any subset of that set that is not equal to that set. The only subset that is not a proper subset is {10, 19, 5, 0}, since that's the set itself. So there are 15 proper subsets.

In general, a set of size n has a total of 2ⁿ subsets, and 2ⁿ - 1 proper subsets.

Okay, this is a puzzle that you have to solve. Let's look at all the parts.

Consecutive odd integers... that means that if x is the first one, then x+2 will be the next largest one, and x+4 will be the largest one.  So if x is 5, x+2 is 7, and x+4 is 9.

Sum means add.  and you want to add the smallest and the middle one. That means x plus x+2

That sum is equal to 27 less than 3 times the largest number.  So the "is equal to" tells us where the equal sign goes.

"less than" means you are subracting 27 FROM something else.   It is three times the larges (x+4) minus 27 on the other side of the equation sign.

Take a minute and write down your equation.

It should look like this:

x+(x+2) = 3(x+4) -27.

The sum of the smallest and the middle number = three times the larger minus 27.

Remember to distribute the three to both terms is (x+4).  When you find x, add two and then four to get the three consecutive odd integers.

PLEASE GIVE BRAINLIEST!